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7k^2-25=30k
We move all terms to the left:
7k^2-25-(30k)=0
a = 7; b = -30; c = -25;
Δ = b2-4ac
Δ = -302-4·7·(-25)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-40}{2*7}=\frac{-10}{14} =-5/7 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+40}{2*7}=\frac{70}{14} =5 $
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